Electric Potential and
Potential Energy

--------------------------------------------------------


Joseph F. Alward, PhD    
Department of  Physics  
University of the Pacific

 

 

 

 

  
Positive   charges accelerate toward regions of lower potential. 
Negative
charges accelerate toward regions of higher potential.

 

 

 

 

 

 

 

 

 

  Equipotential Surfaces                                                 

Alejandro Volta
 (1745-1827)
-----------------------------------------
Points in an electric field may
be labeled according to their
"potential".
Imaginary concentric spheres surrounding
a positive point charge are surfaces of
equal potential:  8 volts, 5 volts, etc.

Equipotential surfaces are perpendicular
to the electric field lines.

 

 

 
 Potentials and Charge
 Distributions
  


Potentials are more positive in regions which
are more positive, or less negative.

 

 

 

 

 

 

 

 

 Equipotential Surfaces                                

Equipotential surfaces are
3-dimensional.

 

 

 

 

Equipotential Surfaces in a Constant Electric Field      

 Equipotential surfaces are planes
 perpendicular to the electric field lines.
 (2-dimensional view)

3-dimensional view
Equipotential surfaces are
imaginary planes.

 

 

 

 

 

  An Equipotential Surface Near Two Opposite Charges

 

 

 

 

  

 

  Equipotential Surfaces and Electric Fields                        

Cross-sectional view of 3-dimensional
equipotential surfaces.  Equipotential
surfaces are perpendicular to the
electric field lines.

Equipotential surfaces (broken lines)
are perpendicular to the electric field.

 

 

 

 

 

 

 

                                                                                             
Positive   charges accelerate toward regions of lower potential. 
Negative
charges accelerate toward regions of higher potential.

 

 

 

 

 

 

 

 

 

 

  Potential Differences and
  Equipotential Surfaces
 

  VA = 500 V    
  VB =  100 V
  VC =  100 V
 DVBA = VB - VA
           = 100 V - 500 V
           = - 400 V
-------------------------------
DVAB = VA - VB
           = 500 V - 100 V
           = 400 V
-------------------------------
DVCB = VC - VB
           = 100 V - 100 V
           = 0

 

 

 

 

   

   Definition of Potential Difference              
W = work done by E

DV = -W/q    

DV
=  -8 J /2 C

      = - 4 V

 

 

 

 

 

Calculating E from Potential Difference    
W  = -q DV        

W =     F Ds        
     = (qE)Ds  

(qE)Ds = -q DV

   E =  -DV / Ds
------------------------
What is the sign of DV ?

If E is positive, E points
in the direction of  Ds.

  

 

 

 

 

 

   Calculating E from Potential Difference               

What is E between the plates?
DV = VB - VA
       = 12 - 0
       = 12 V
Ds   = 0.02 m
E     = - DV / Ds
       =
-12 /0.02
       = -600 V/m
--------------------
E is negative, so it points
opposite to Ds:  E points
from B to A.

 

 

 

 

    Calculating E from Potentials

  What is E near top of this person's
   head, at the 100 V equipotential
   surface?
Person in contact with ground is at
same potential as ground:  V = 0.

Point is roughly midway between
200 V and 0 V surfaces.

Estimated separation:   Ds = 30 cm
                                        = 0.30 m

E    = -DV / Ds
      =  -(0 - 200)/0.30
      = 667 V/m

 

 

 

   

 

  Calculating E from Potentials

  What is the electric field E?
E    = -DV / Ds
     

DV = 2 V
Ds = 1 x 10-3 m

E = 2000 V/m
----------------

Note:  E always
points toward
lower potentials.

 

 

 

  

 

                                                                                               
Positive   charges accelerate toward regions of lower potential. 
Negative
charges accelerate toward regions of higher potential.

 

 

 

 

 

 

 

 

  

 

 

 E Points Toward Lower Potentials
  Positive    Charges Move Toward Lower Potentials
  Negative Charges Move Toward Higher Potentials                    

Electric field arrows point toward
regions of lower potential.

 

 

 

 

 

  

 

 

  Metals Are Equipotential Surfaces                                           
How much work would it take to drag over the
surface a positive charge q from Point A to
Point B?
---------------------------------------------------------------
Moving along the surface, DV = 0, so

E//    = -DV / Ds
        = 0

E// = component of E parallel to the surface

so the electric force F// = qE// = 0.

W = F// Ds
     = 0

 

 

 

 

  

                                                                                                  
 No work is required to move charges along equipotential surfaces.

 

 

 

 

 

 

  

 

 

 

 

 

  Heart Equipotential Surfaces
Which way is the negative ion current
flowing across this heart? The positive ion
current?

 

 

 

 

 

 

 

 

 

   The Potential Due to a Single Point Charge                               

 What is the potential 2 meters away
 from a one nano-coulomb charge? 
 V = V(r) = kq/r
  This expression for potential is only
  valid for a single point charge.
 -------------------------------------------------

k = 9 x 109 (SI units)
q = 1 x 10-9 C
 r = 2 m

V = 9 x 109 (1 x 10-9) / 2
    = 4.5 volts
    = 4.5 V
-------------------------------------------------
What is the potential at any point
a distance r = 1.5 meter from the
charge?             Answer:  6 V

 

 

 

 

 

 

 

    Work and Potential                                                                        

  How much work would be done by
  the electric field if Q = 20 C were
  moved from A to B?
W   = -QDV
 Q   = 20 C
DV  = 8V - 4.5 V
        = 3.5 V

W = -(20 C) (3.5 V)
     = -70 J    (note:  negative)
----------------------------------------
How much work was done by
the agent which moved the
charge?

Answer:  +70 J  

 

 

 

 

 

 

  

   
Positive   charges accelerate toward regions of lower potential. 
Negative
charges accelerate toward regions of higher potential.

 

 

 

 

 

 

 

 

 

  Breakdown of Air                                   

 

 

 

 

 

 

  Lightning Energy                                                                       

 A charge q = - 30 C is pushed
 from cloud to ground.
  DV =  2 x 108 V.
Energy gained = Work done by electric field
                      = -qDV
                      = -(-30 C)(2 x 108 V)
                      = 60 x 108 J
------------------------------------------------------------
How many kilograms of water at 20 C
could be converted into steam at 100 C?
(For help with this, click here to go to the
lecture on specific and latent heats.)

Answer:  2308 kg (2.3 cubic meters)
(What would this lightning bolt do to a
human?)

 

 

 

 

 

 

 

  Calculate the Potential Due to Two Point Charges     

           What is the potential at Point P?
Use V = kq/r for each charge,
then add the potentials:

V = (9 x 109)(4 x 10-9)/12
    = 4 V

V = (9 x 109)(6 x 10-9)/27
    = 2 V

Total Potential:  6 V
----------------------------------------
 How much work was done to
 assemble these charges?

   

 

 

 

 

 

   Work Done in Assembling a System of Charges         

 
How much work would you have to do to
assemble this system of charges?
The work required to bring the first
charge (4 nC) in from infinity is zero.

The work done by the electric field
when the 6 nC charge is brought in
is W =  - (6 nC) DV.  The work
done by some external agent (you)
is the negative of this work:


Wyou  = (6 nC) DV.

DV = ?

 

 

 

 

  The Electric Potential Energy of a Charge Configuration    

V =  (9 x 109)(4 x 10-9)/36
    = 1 V

 DV = 1 V - 0 V
       = 1 V
  W = qDV
       = (6 nC) (1 V)
       = 6 nJ

 This is the work done by an external
 agent to assemble this system of
 charges; it's not the work done by
 the electric field.    

This is the "electric potential energy"
of this system.

 

 

 

 

 

 

 

 

 

 

 

 

  

 Potential Energy of Three
 Charges on a Line 

Solution:  Bring in first charge for free.  Second
charge sees the potential field of the first.  Third
charge sees the sum of the two potential fields.

 

 

 

 

 

 

 

                                                                                                    
 No work is required to move charges along equipotential surfaces.

 

 

 

 

 

 

 

 

 

   Conservation of Energy Example                              
Energy = kinetic + potential
     E    = 1/2 mv2 + qV
           = KE + EPE
------------------------------------
 EB = EA
 1/2 mvB2 + qVB = 1/2 mvA2 + qVA
 vA= 0
 vB = [2q(VA - VB)/m]1/2

 Solve for speed v:  
 
 v = 5 m/s

 

 

 

 

  

 

  Electrocardiography                               

 

 

 

 

  

 

 

  Electroencephalography                        

Greek:   enkephalos:  in the head; brain.  The alpha
rhythm is the "resting" rhythm.

 

 

 

 

 

 

 

 

  

 

  Electroretinography                                    

Measuring the electrical activity of the retina.

 

 

 

 

 

 

 

 

    The Potential Field of a Blood Drop                

  Normal                       Osteosarcoma              Leukemia

 Electrosensitive liquid crystal changes color with voltage.
 Blue:  150 V     Green:  120 V     Yellow:  90 V     Red:  50 V

 

 

 

 

 

 

  Potential Field of Brain     

A map of the equipotentials in the brain of
a person with epilepsy.

 

 

 

 

 
   300,000 Volts and Still Alive      
Electrons flow briefly onto this
person's body, lowering her
potential to -300,000 volts, the
same as the wire's potential.

How close could her hand
or foot come to the tower
(which is grounded, V = 0)
without her being electrocuted?
                       

 

 


  Conceptual Questions:

Base your answers to the following questions on the equation:  E    = -DV / Ds.
----------------------------------------------------------------------------------------------------------------
1.  If the potential in a region of space is constant, is the electric field necessarily
     zero in the region?

2.  If the electric field is zero in a region of space, must DV be zero between points
      in that region?

3.  If E is zero in a region of space, must the potential V be zero at all points in that
     region, too?